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Dafna1 [17]
3 years ago
9

the formula an=1.5 (an-1) with an initial value of 40 describes a sequence. Use the explicit formula to determine the 5th term o

f the sequence.
Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

\text{If } a_n=1.5(a_n-1) \text{ this is a geometric sequence with a ratio of 1.5. The first term is 40. }a_n=40(1.5)^{n-1},\ a_5=40(1.5)^4=202.5

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2 classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the large
iogann1982 [59]
X + Y = 50
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X = 28
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3 years ago
A right triangle has a hypotenuse C=12cm and a an angle A= 30°. find the length of side a, witch is opposite angle A
Alisiya [41]
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7 0
3 years ago
Find the angle measure to the nearest degree. <br> cos A = 0.7431<br> How do I do this?
svet-max [94.6K]

Answer:

Step-by-step explanation:

If you are looking for a missing angle measure, you use the 2nd button and the cos button.  Make sure, first off, that your calculator is in "degree" mode by hitting the "mode" button and making sure that the "degree" is highlighed and not the "radian".  Then hit "clear".  Once you know that you are in the correct mode, hit "2nd" then "cos" and you will see this on your screen:

cos^{-1}(

Inside the parenthesis you will enter your decimal, so it looks like this now:

cos^{-1}(.7431

You do NOT have to close the parenthesis, but you can if you want to.  Then hit "enter" to get that the angle that has a cosine of .7431 is 42.0038314 or, to the nearest degree, 42

6 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

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X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
Determine three consecutive odd integers whose sum is 2097.
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Answer: 698 699 700

Step-by-step explanation:

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