the formula an=1.5 (an-1) with an initial value of 40 describes a sequence. Use the explicit formula to determine the 5th term o

f the sequence.

Mathematics

1 answer:

nika2105 [10]3 years ago

3 0

$\text{If } a_n=1.5(a_n-1) \text{ this is a geometric sequence with a ratio of 1.5. The first term is 40. }a_n=40(1.5)^{n-1},\ a_5=40(1.5)^4=202.5$

You might be interested in

2 classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the large

iogann1982 [59]

X + Y = 50
X = Y + 6
X = 28
Y = 22
28 + 22 = 50
28 - 22 = 6 (28= 22 + 6)
There are 28 students in the larger class.
Hope this helps :)

7 0

3 years ago

A right triangle has a hypotenuse C=12cm and a an angle A= 30°. find the length of side a, witch is opposite angle A

Alisiya [41]

Use the sin identity to find that side. Sin(30) = a/12...12 sin(30) = a, and a = 6

7 0

3 years ago

Find the angle measure to the nearest degree. <br> cos A = 0.7431<br> How do I do this?

svet-max [94.6K]

Answer:

Step-by-step explanation:

If you are looking for a missing angle measure, you use the 2nd button and the cos button. Make sure, first off, that your calculator is in "degree" mode by hitting the "mode" button and making sure that the "degree" is highlighed and not the "radian". Then hit "clear". Once you know that you are in the correct mode, hit "2nd" then "cos" and you will see this on your screen:

$cos^{-1}($

Inside the parenthesis you will enter your decimal, so it looks like this now:

$cos^{-1}(.7431$

You do NOT have to close the parenthesis, but you can if you want to. Then hit "enter" to get that the angle that has a cosine of .7431 is 42.0038314 or, to the nearest degree, 42

6 0

3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$