Question

John rolls a six-sided number cube twice. What is the probability of getting an even number and then an odd number?

Answer 1

Multiply 3/6 x 3/6 and then reduce

Answer 2

Answer: $\dfrac{1}{4}$

Step-by-step explanation:

Given : John rolls a six-sided number cube twice.

Total number of outcomes on a fair cube = 6

When we roll two dices , then the total number of outcomes :-

$6\times6=36$

Number of favorable outcomes of getting an even number and then an odd number :-

$3\times3=9$   [since there are 3 odd and 3 even numbers on it]

Now, the probability of getting an even number and then an odd number =

$\dfrac{9}{36}=\dfrac{1}{4}$