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Minchanka [31]
3 years ago
8

What is the volume of cylinder B?

Mathematics
1 answer:
timama [110]3 years ago
6 0

Step-by-step explanation:

Height of the cylinder A(h1)=5cm

CSA of cylinder A(CSA1)=18cm^2

Height of the cylinder B (h2)=10cm

CSA of cylinder B (CSA)=?

Since cylinder A and B are similar,

h1=xh2

or,5cm=x*10cm

or,x=1/2

Similarly,

CSA1=xCSA2

or,18cm^2=1/2*CSA2

or,CSA2=36cm^2

We khow that,

Volume of cylinder B (V2)= CSA2 * h2

=36cm^2*10cm

=36cm^3

Follow me for more solution like this.....

THANK YOU

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Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64
tino4ka555 [31]

a.

x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}

By Fermat's little theorem, we have

x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5

x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7

5 and 7 are both prime, so \varphi(5)=4 and \varphi(7)=6. By Euler's theorem, we get

x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5

x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7

Now we can use the Chinese remainder theorem to solve for x. Start with

x=2\cdot7+5\cdot6

  • Taken mod 5, the second term vanishes and 14\equiv4\pmod5. Multiply by the inverse of 4 mod 5 (4), then by 2.

x=2\cdot7\cdot4\cdot2+5\cdot6

  • Taken mod 7, the first term vanishes and 30\equiv2\pmod7. Multiply by the inverse of 2 mod 7 (4), then by 6.

x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6

\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}

b.

x^5\equiv3\pmod{64}

We have \varphi(64)=32, so by Euler's theorem,

x^{32}\equiv1\pmod{64}

Now, raising both sides of the original congruence to the power of 6 gives

x^{30}\equiv3^6\equiv729\equiv25\pmod{64}

Then multiplying both sides by x^2 gives

x^{32}\equiv25x^2\equiv1\pmod{64}

so that x^2 is the inverse of 25 mod 64. To find this inverse, solve for y in 25y\equiv1\pmod{64}. Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that (-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}.

So we know

25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}

Squaring both sides of this gives

x^4\equiv1681\equiv17\pmod{64}

and multiplying both sides by x tells us

x^5\equiv17x\equiv3\pmod{64}

Use the Euclidean algorithm to solve for x.

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that (-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}, and so x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}

5 0
3 years ago
Lucy went to buy apples, she bought the first two for the full price and the last one for half the price. Is the relationship be
Anit [1.1K]
No it is not proportional. Since she brought the last apple for 1/2 the price, the equation won’t be linear (straight line) anymore so it won’t be proportional. Proportional means the same unit rate.
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3 years ago
Need help due tomorrow
nika2105 [10]
250cm^2

To find the area of shape B we need to find the factor by which you multiply to get from 12 to 15. To find this we divide 15 by 12 to get 1.25. We now multiply the area of shape A (200) by the factor 1.25 to get the answer. The answer is 250cm^2.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
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3 years ago
What is the GCF of:<br> 15x^2y and 20xy
azamat

Answer:

5xy

Step-by-step explanation:

x and y can only go into both into once

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How to solve 3+p=8 step by step
AURORKA [14]
3+p=8
-p      -p
3=8-p
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5 0
3 years ago
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