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Sidana [21]
2 years ago
7

How many real solutions are there for the quadratic equation below?

Mathematics
1 answer:
olga55 [171]2 years ago
7 0

Answer:

2 solutions

Step-by-step explanation:

2 solutions

3/4 - i\sqrt{47}/4

3/4 + i\sqrt{47}/4

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A line passes through the points (1, –6) and (4, 3).
Marina CMI [18]

Answer:

y = 3x - 9

Step-by-step explanation:

We first need to find the slope (m)

m = \frac{y_2-y_1}{x_2-x_1} = \frac{3 - (-6)}{4-1} = \frac{9}{3} = 3

y = mx + b

y = 3x + b

(4, 3)

y = 3x + b

3 = 3(4) + b

3 = 12 + b

-12  -12

-9 = b

(1, –6)

y = 3x + b

-6 = 3(1) + b

-6 = 3 + b

-3   -3

-9 = b

y = 3x - 9

To check:  (1, –6)

y = 3x - 9

-6 = 3(1) - 9

-6 = 3 - 9

-6 = -6

Hope this helps!

6 0
2 years ago
Convert as indicated <br><br> 10 lb 7 oz to ounces
slega [8]

Answer:

167oz

Step-by-step explanation:

There are 16oz in 1 lbs so we multiply the 10lbs by 16 to get oz.

10lbs * 16oz = 160oz

Now we add the 7oz because that's already in the correct unit.

160oz + 7oz = 167oz

8 0
3 years ago
EXERCISE - 2.1
seraphim [82]

Answer:

5

Step-by-step explanation:

the degree is 5

As degree means the largest exponent of a term

8 0
3 years ago
How long does it take a car to travel 200 miles at a constant speed of 25 miles per hour?
pashok25 [27]
8 hours should be your answer. 
8 0
3 years ago
Read 2 more answers
How can I factorise (2x cubed - 5x + 3) ?
PilotLPTM [1.2K]
2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}

therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}
7 0
3 years ago
Read 2 more answers
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