Your answer is the first option, 8.0. You can find this by using the sine rules for sides, so:
10/sin(90) = x/sin(53)
× sin(53)
7.98 = x
And 7.98 rounded to the nearest tenth is 8.0.
I hope this helps!
Answer:
The 99% confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is 
The sample mean is 
The standard deviation is 
Given that confidence is 99% then the level of significance is mathematically represented as


Next we obtain the critical values of
from the normal distribution table
The value is
Generally the margin for error is mathematically represented as

=> 
=> 
The 99% confidence interval is mathematically represented as

=> 
=> 
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
880 high-quality version
Step-by-step explanation:
I think the below is your full question:
<em>A Web music store offers two versions of a popular song. The size of the standard version is 2.1megabytes (MB). The size of the high-quality version is 4.5 MB. Yesterday, there were 1290 downloads of the song, for a total download size of 4821 MB. How many downloads of the high-quality version were there?</em>
Here is my answer:
Let x is the number of high-quality version
So the number of standard version= 1290 - x
We also know: total download size of 4821 MB. which means:
4.5x + 2.1(1290-x) = 4821
<=> 4.5x+2709-2.1x=4821
<=> 2.4x=2112
<=> x=880
So there were 880 high-quality version
Answer:
there are one thousand (1,000) meters in a kilometer. So, 5,000 plus 10,000 is 15,000 meters.
Step-by-step explanation: