What are the four points of intersection between 4x^2 + y^2 - 4y - 32 = 0 and x^2 - y - 7 = 0 ? Solve algebraically
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in short, you simply pick a few random "x" values, to get the "y", and that's your point, for example say x = 2, then y = -(2)² - 4 => y = -8, that gives us the point of (2, -8), and so on.
we can start off by finding the vertex, the U-turn of the graph, and then just pick a point to its left side and a point to its right side, and we can get the vertex of that by
and since it's a vertical parabola, the axis of symmetry comes from the x-coordinate of the vertex, namely x = 0, check the picture below.
Sides given by
- 10
- x+2
- x+5
- 2x+3
Opposite sides must be equal
Let's check once
Find sides now
- 10in
- 2+2=4in
- 2+5=7in
- 2(2)+3=4+3=7in
One pair of opposite sides are equal but others not .
- It's a trapezium.