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3 years ago

15

7 less than -2 times a number x is greater than or equal to 41 write a inequality for the statement above and find out a solutio

n

1 answer:

Svet_ta [14]3 years ago

6 0

-2x-7 (greater than or equal to sign) 41

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Given 2 lines cut by a transversal, what would the m<7 have to be if m <4=85 for the lines to be parallel and what is the

nlexa [21]

Answer:

85º

Step-by-step explanation:

<7=<4 since we know the lines are parallel, and intersected at the same angle

Therefore, <7=85º.

8 0

2 years ago

15 + brainliest help me please

Fiesta28 [93]

2f +4f +2 -3
combine the like terms to get 6f-1

so yes they are equivalent

2f+4f+2-3 at f=3 would also be 17

8 0

3 years ago

Read 2 more answers

.At a certain animal shelter, the ratio of puppies to adult dogs is 7 to 4. This week there are a total of55 dogs in the shelter

Advocard [28]

Answer:

There are 35 adult dogs and 20 puppies

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Step-by-step explanation:

<em>Represent the puppies with P and the Adult dogs with A</em>

Given

$A : P = 7 : 4$

Dogs = 55

Required

Determine A and P

First, we need to sum the ratios;

$Total = A + P$

$Total = 7 + 4$

$Total = 11$

Adult Dogs is then calculated as follows;

$A = \frac{A\ Ratio}{Total} * Dogs$

$A = \frac{7}{11} * 55$

$A = \frac{385}{11}$

$A = 35$

Puppies is calculated by subtracting the number of adult dogs from the total

$P = Dogs - Adult\ Dogs$

$P = 55 - 35$

$P = 20$

<em>Hence;</em>

<em>There are 35 adult dogs and 20 puppies</em>

3 0

3 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago

A forest covers 43,000 acres. A survey finds that 0.7% of the forest is old-growth trees. How many acres of old-growth trees

Goryan [66]

Answer:

301 acres

Step-by-step explanation:

43,000 acres of forest

0.7% is old-growth

0.7% = 0.007

43,000 * 0.007 = 301 acres

7 0

3 years ago