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mel-nik [20]
3 years ago
12

You fly a hot air balloon 3.5 miles above the ground. What is the measure of BD⌢, the portion of Earth that you can see? Round y

our answer to the nearest tenth. (Earth's radius is approximately 4000 miles.)

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

\Delta s \approx 334.545\,m

Step-by-step explanation:

Let assume that Earth is a sphere, the following trigonometric diagram is constructed and presented below. The central angle is given by this inverse trigonometric equation:

\theta = 2\cdot \cos^{-1} \left(\frac{r}{r+h} \right)

\theta = 2\cdot \cos^{-1}\left(\frac{4000\,mi}{4000\,mi+3.5\,mi} \right)

\theta = 4.792^{\circ}

The distance of the portion of Earth that can be seen is:

\Delta s = \frac{4.792^{\circ}}{360^{\circ}}\cdot (2\pi)\cdot (4000\,mi)

\Delta s \approx 334.545\,m

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Step-by-step explanation:

We have been given a table, which represents the projected value of two different houses for three years.


Part A:

\text{Increase in value of house 1 after one year}=294,580-286,000

\text{Increase in value of house 1 after one year}=8580

\text{Increase in value of house 1 after two years}=303,417.40-294,580

\text{Increase in value of house 1 after two years}=8837.4

We can see from our given table that the value of house 1 is not increasing at a constant rate, while a linear function has a constant rate of change, therefore, an exponential function can be used to describe the value of the house 1 after a fixed number of years.

\text{Increase in value of house 2 after one year}=295,000-286,000

\text{Increase in value of house 2 after one year}=9,000

\text{Increase in value of house 2 after two years}=304,000-295,000

\text{Increase in value of house 2 after two years}=9,000

We can see from our given table that the value of house 2 is increasing at a constant rat that is $9,000 per year. Since a linear function has a constant rate of change, therefore, a linear function can be used to describe the value of the house 2 after a fixed number of years.

Part B:

Let x be the number of years after Dominique bought the house 1.

Since value of house 1 is increasing exponentially, so let us find increase percent of value of house 1.

\text{Increase }\%=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

\text{Increase }\%=\frac{294,580-286,000}{286,000}\times 100

\text{Increase }\%=\frac{8580}{286,000}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

\text{Increase }\%=\frac{303,417.40-294,580}{294,580}\times 100

\text{Increase }\%=\frac{8837.4}{294,580}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

Therefore, the growth rate of house 1's value is 3%.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For growth b is in form (1+r), where, r is rate in decimal form.

3\%=\frac{3}{100}=0.03

Upon substituting our values in exponential function form we will get,

f(x)=286,000(1+0.03)^x, where, f(x) represents the value of the house 1, in dollars, after x years.

Therefore, the function f(x)=286,000(1.03)^x represents the value of house 1 after x years.

Let x be the number of years after Dominique bought the house 2.

We can see that when Dominique bought house 2 it has a value of $286,000. This means that at x equals 0 value of house will be $286,000 and it will be our y-intercept.

Since value of house 2 is increasing 9000 per year, therefore, slope of our line be 9000.

Upon substituting these values in slope-intercept form of equation (y=mx+b) we will get,

f(x)=9000x+286,000, where, f(x) represents the value of the house 2, in dollars, after x years.

Therefore, the function f(x)=9000x+286,000 represents the value of house 2 after x years.

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Since values in exponential function increases faster than linear function, so the value of house 1 will be greater than value of house 2.

Let us find the value of house 1 and house 2 by substituting x=25 in our both functions.

f(25)=286,000(1.03)^{25}

f(25)=286,000*2.0937779296542148

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We can see that value of house 1 after 25 years will be approx $598,820.48.

f(25)=9000*25+286,000

f(25)=225,000+286,000

f(25)=511,000

We can see that value of house 2 after 25 years will be approx $511,000.

Since $511,000 is less than $598820.48, therefore, value of house 1 is greater than value of house 2.

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