Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.
Answer:
A=the outcome is odd, B=the outcome is even
Is mutually exclusive because you can't have a number that is even and odd at the same time.
Hope this helps :)
2x+4y=16
x-7=-4y
4y=16-2x
<span>4y=16-2(-4y+7)
4y=16+8y-14
-4y=2
-4y/-4=2/-4
<u>y=-0,5</u>
2x=16-4(-0,5)
2x=16+2
2x/2=18/2
<u>x=9
</u>
C</span>
Given: w²+9=6w [0, 3, 6, 9]
We need to substitute each number for w and find which works
Sub Zero: 0²+9=6×0
Simplify: 9=0. 9 does not equal 0, so it is not 0
Sub Three: 3²+9=6×3
Simplify: 9+9=18
Addition: 18=18
The statement 18=18 is true, therefore we have our answer.
Answer: The second option is correct. 3 would be the correct number to substitute to make the equation correct.
The answer is C
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