Answer:
12
Step-by-step explanation:
quisis
During class this was a 2 question review of many we did while we were seeing colleges we might want to go to.
Answer:
The area of the sector is 84.8 in.² to the nearest tenth
Step-by-step explanation:
∵ the clock is a circle
∴ The measure of angles between each two hours = 360° ÷ 12 = 30°
∵ At 8 o'clock the hour hand pointed on 8 and the minute hand pointed on 12
∴ There are 4 angles between the two hands
∴ The central angle subtended by the arc = 4 × 30° = 120°
∵ The Area of the sector =
where x is the central angle subtended by this arc
∴ Area sector =
× π × (18/2)²
∴ Area sector =
× π ×81 = 27π = 84.8 in² to the nearest tenth
Wow ! There's so much extra mush here that the likelihood of being
distracted and led astray is almost unavoidable.
The circle ' O ' is roughly 98.17% (π/3.2) useless to us. The only reason
we need it at all is in order to recall that the tangent to a circle is
perpendicular to the radius drawn to the tangent point. And now
we can discard Circle - ' O ' .
Just keep the point at its center, and call it point - O .
-- The segments LP, LQ, and LO, along with the radii OP and OQ, form
two right triangles, reposing romantically hypotenuse-to-hypotenuse.
The length of segment LO ... their common hypotenuse ... is the answer
to the question.
-- Angle PLQ is 60 degrees. The common hypotenuse is its bisector.
So the acute angle of each triangle at point ' L ' is 30 degrees, and the
acute angle of each triangle at point ' O ' is 60 degrees.
-- The leg of each triangle opposite the 30-degree angle is a radius
of the discarded circle, and measures 6 .
-- In every 30-60 right triangle, the length of the side opposite the hypotenuse
is one-half the length of the hypotenuse.
-- So the length of the hypotenuse (segment LO) is <em>12 </em>.
Answer:
32 ounces of cumin
Step-by-step explanation:
You have a ratio of
Tumeric : Cumin
5 : 4
40 ounces : ?
You divide 40 by 5 and get 8.
So you do 8 x 4 and get 32 ounces
(MAKE BRAINLIEST IF I HELPED)
Answer:
x=10
Step-by-step explanation::
We can use Triangle angle bisector theorem and proportions to solve this problem. We put the small triangle side over the large triangle side
8 x+4
------ = ------------
12 2x+1
Using cross products
8(2x+1) = 12(x+4)
16x+8 =12x+48
Subtract 12x from each side
16x-12x +8 = 12x-12x+48
4x+8 = 48
Subtract 8 from each side
4x+8-8 = 48-8
4x = 40
Divide by 4
4x/4 = 40/4
x = 10