All categories

3 years ago

Help please i need it done quickly

Mathematics

2 answers:

Mariulka [41]3 years ago

8 0

5.24 and 2.85 I think that’s correct

Katena32 [7]3 years ago

4 0

First person who responded is right

You might be interested in

35. Two angles form a linear pair. The measure of

earnstyle [38]

Ye ye ye ye ye yee egensbdnsys

5 0

2 years ago

Graph the line with slope 1/3 passing through the point (5,-5).

-Dominant- [34]

$slope=\dfrac{\Delta y}{\Delta x}\\\\slope=\dfrac{1}{3}\to\Delta y=1\ and\ \Delta x=3\\\\1\ unit\ up\ and\ 3\ units\ right.\\\\\text{We mark the point (-5, 5). Then move it 1 unit up and 3 units to the right}\\\\Look\ at\ the\ picture.$

7 0

3 years ago

Use a definition, postulate, or theorem to find the value of x in the figure described.

Yuri [45]

The Definition of Linear Pair states that both ∠ABC and ∠CBD are equal to 180 degrees. In the question, this tells you that
m∠ABC and m∠CBD = (3x − 6).
So, you're equation should be (3x - 6) + (3x - 6) = 180.
You would then solve to get 6x - 12 = 180, 6x = 192, x = 32
x=32, and we used the Linear Pair Theorem (C)

5 0

3 years ago

MATH PLEASE HELP

BlackZzzverrR [31]

Answer:

$122.10

Step-by-step explanation:

Note cm is changed to ft

Perimeter of the garden:

P = 2(14 + 23) = 74 ft

The price of fencing:

74*$1.65 = $122.10

5 0

3 years ago

Does anyone know how to do this help please

statuscvo [17]

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-

$\rm\implies y = 3^2-3-6\\$

$\rm\implies y = 9 - 3 - 6 \\$

$\rm\implies y = 0$

Put x = -2 :-

$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

$\rm\implies y = -4$

Put x = -1 :-

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

$\rm\implies y = -6$

Put x = 1 :-

$\rm\implies y = 1^2+1-6\\$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

Put x = 2 :-

$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

$\rm\implies y = 2$

Put x = 3 :-

$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

$\rm\implies y = 6$

Final table :-

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

7 0

3 years ago