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2 years ago

KHAN ACADEMY Find BC in AABC. Round to the nearest tenth. BC=

Mathematics

2 answers:

MrRissso [65]2 years ago

3 0

Answer:

the answer to this is BC= 83

Dennis_Churaev [7]2 years ago

3 0

Answer:

BC = 83

as the sum of angles in a triangle is equal to 180

53+44+x=180

97+x=180

x=180-97

therefore,BCis equal to 83

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Zinaida [17]

(- 5, - 6 )

for x- coordinate x + 5 = 0 ⇒ x = - 5

given f(x) ± c , the value of c translates the graph vertically up/down by ± c

here c = - 6 , thus graph is shifted down by - 6

thus the vertex = (- 5, - 6)

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2 years ago

F(x)=3x^3-12x^2+9x what the factor<br>

alexandr1967 [171]

Answer:

f(x) = 3x(x-1)(x-3)

Step-by-step explanation:

f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =

= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =

= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)

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2 years ago

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Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

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2 years ago

A box of crayons costs $1.75, including tax. Mr. Valentino wants to purchase boxes of crayons for his class and has a $25 budget

densk [106]

Answer:

1.75x ≤ 25

Step-by-step explanation:

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3 years ago

Pamela has 4 pink ribbons, 3 green ribbons, and 1 blue ribbon. what fraction of Pamela's ribbons are green?

Brrunno [24]

The total number of ribbons is 8 because 4 + 3 + 1 is 8
The number of green ribbons is 3
That means that 3 out of the 8 ribbons are green
Answer: 3/8

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2 years ago

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