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lakkis [162]
3 years ago
9

Dina and Masha start cycling on a 20 km bike path at the same time. When Dina reaches the end of the path, Masha still has 4 km

of the path left to cycle. If Dina's cycling speed is 10 km/h, how much time longer will Masha need to complete the path?
Mathematics
2 answers:
Ahat [919]3 years ago
8 0

Answer:

30 minutes

Step-by-step explanation:

sammy [17]3 years ago
7 0

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

Speed=\frac{distance}{time}\\10=\frac{20}{time}\\time=\frac{20}{10}\\ time=2\ hours

The time taken by Dina is 2 hours. As masha started with dina but she was 4 km of the path left to cycle,

her distance covered in 2 hours was:

Distance\ covered\ by\ Masha\ in\ 2\ hours=20-4\\=16 km

So we know the time and distance:

Now,

Speed\ of\ Masha=\frac{distance}{time}\\ =\frac{16}{2}\\ =8\ kilometer\ per\ hour

We have to calculate the time that will be needed by MAsha to complete the track:

As we know the speed and remaining distance

Speed=\frac{distance}{time}\\8=\frac{4}{time}\\ time=\frac{4}{8}\\time=0.5\ hours

Masha needs 0.5 hour to complete the track ..

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Find the sum of the first 20 terms of the arithmetic sequence 4, -4, -12, -20​
Vsevolod [243]

Answer:

The sum of the first 20 terms is -1440.

Step-by-step explanation:

We want to find the sum of the first 20 terms of the arithmetic sequence:

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The sum of an arithmetic sequence is given by:

\displaystyle S=\frac{k}{2}(a+x_k)

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Since we want to find the sum of the first 20 terms, <em>k</em> = 20.

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x_n=a+d(n-1)

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x_n=4-8(n-1)

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3 years ago
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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

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Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

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substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

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The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

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