The answer is: False.
If a logarithm is written without a base <span>it IS NOT a natural logarithm.</span>
The explanation is shown below:
1. I<span>f a logarithm is written without a base, you must assume the base is 10. It is written as below:
log(x)
</span>
2. It is important to know that the base <span>a natural logarithm is the irrational number e. It is written as below:
ln(x)</span>
7.2, PQ is in the middle of two corresponding angles (M and O)
Let's call the smaller number x:
y-x=5
xy=104
y-x=5 can be rewritten as y=x+5
Substituting this into the second equation gives:
x(x+5)=104
x^2+5x=104
x^2+5x-104=0
Then simply solve as a quadratic:
x^2+13x-8x-104=0
x(x+13) -8(x+13)=0
(x-8)(x+13) = 0
x=8,-13
the question said the numbers are positive, so x=8
if x=8,
y=x+5
y=13
So the two numbers are 8 and 13.
B) 40,000. the first 2 is 20,000. the second 2 is 2. 20,000 times 2 is 40,000
Answer:
no idea but hi Hannah
Step-by-step explanation:
