Answer:
90
12
0.0154
Step-by-step explanation:
a) #Possible experimental run=#Temp x #pres x #cat=3x5x6=90
b) #Possible experimental run=(Temp. lowest) x 2.pres x #cat=1x2x6=12
c) C="different catalyst is used on each run"
In the first, I can choice 6 of 6 catalysts, in the second 5 of 6,...
then: P(C) = 6/6 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6 = 5/324 = 0.0154
He is wrong because as long as they have the same terms/ variables behind the number it doesn’t matter about if it is positive or negative
honestly I think that if Leo included each forward to be equal then it would be 2.5 difference on each team
im not one 100 on this but I think that each forward was raised to be equal at 2.5
Mark me brainliest plsssssss
-4 x 9= -36 and the when you add 5 to -36 you get -31. Hope this helps
