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Volgvan
3 years ago
7

Use inductive reasoning to find the next term in this sequence 2,3,5,9,17. Then explain the rule for the pattern.

Mathematics
1 answer:
NISA [10]3 years ago
7 0

We have been given the sequence 2,3,5,9,17.

We can write the terms of this sequence as

2=2^0+1\\
3=2^1+1\\
5=2^2+1\\
9=2^3+1\\
17=2^4+1\\

From the above term we can see that for the first term we take exponent 0 on 2 and then add 1 .

For second term we take exponent 1 on 2 and then add 1 .

For third term we take exponent 2 on 2 and then add 1 .

Using this fact for the next term of the sequence i.e. 6th term, we can take exponent 5 on 2 and then add 1 .

Therefore, next term of the sequence is given by

2^5+1\\
=32+1\\
=33

Therefore, the next term is 33.

Using the above facts, the pattern is given by

a_n=2^{n-1}+1

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joja [24]

Answer:dont know

Step-by-step explanation:

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8 0
2 years ago
Unit rates... please help
harina [27]
When rates are expressed as a quantity of 1 such as 2 feet per second or 5 miles per hour, that is the definition of unit rates.





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3 0
3 years ago
If a student has an average exam score between 70 and​ 79, he will earn a grade of C in his algebra course. Suppose he has three
goldenfox [79]

Answer:

(64,86.5)

Step-by-step explanation:

find the case where he gets 70 and the case where he gets 79

if his average is 70:

(75+62+85+2x)/5=70

(222+2x)/5=70

222+2x=350

2x=128

x=64

if his average is 79:

(75+62+85+2x)/5=79

(222+2x)/5=79

222+2x=395

222+2x=395

2x=173

x=86.5

7 0
3 years ago
Find x and y. Give reasons to justify your solution. AB, CD, EF, and GH are straight lines.
8_murik_8 [283]

Answer:

X= 32 Y= 35

Step-by-step explanation:

We know FOB is parralel to AOE meaning x= 32

also, COH = 90 so GOD is also 90.

a straight angle is 180, so

23+90+x or 32= 145,

180-145=35,

y=35

6 0
3 years ago
Read 2 more answers
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
ella [17]

Answer:

137

Step-by-step explanation:

Use the model A = Pe^(kt), where P is the initial number and k is the growth constant.  Then, in case 1,

300 = Pe^(k*3)

and in case 2,

4000 = Pe^(k*10).  We need to find P and e^k.

300 = Pe^(k*3) can be rewritten as (300/P) = [e^k]^3, which in turn may be solved for e^k:

∛(300/P) = e^k

Now we go back to 4000 = Pe^(k*10) and rewrite it as (4000/P) = [e^k]^10.  Substituting ∛(300/P) for e^k, we obtain:              

(4000/P) =  (300/P )^(10/3)

which must now be solved for P.  Raising both sides by the power of 3, we get:

(4000/P)^3 = (300/P)^10.  Therefore,

4000^3       300^10

------------- = -------------

   P^3             P^10

which reduces to:

4000^3       300^10

------------- = -------------

       1             P^7

or

        1         P^7

------------  =  -----------

4000^3       300^10

or:

           300^10

P^7 = ---------------- = 9.226*10^13  = 92.26*10^12

           4000^3

Taking the 7th root of both sides results in P = (92.26*10^12)^(1/7), or

                                                                        P = 137.26

The initial number of bacteria was 137.

7 0
2 years ago
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