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satela [25.4K]
2 years ago
15

Stan borrows $5,500 at a rate of 12% interest per year. What is the amount due at the end of 5 years if the interest is compound

ed continuously? In your final answer, include your calculations.
Mathematics
2 answers:
daser333 [38]2 years ago
6 0

Answer:

1.) Without compound interest, you would earn only $8800.00. This means that thanks to the power of compound interest you will earn an additional $1191.83 in interest at the end of the 5 year term.

2.) Using the compounded interest formula, you will earn $22883.01 after the 7 year term.

3.) Because of the negative interest, the compounded amount is only $695,929.30.

4.) Putting money in a saving account is saving money with a lower earning compared to investments. Investments have the higher potential of earning more than just having a basic savings account.

Step-by-step explanation:

aleksandr82 [10.1K]2 years ago
6 0

If you don't have compound interest, you would earn only $8800.00. This means that thanks to the power of compound interest you will earn an additional $1191.83 in interest at the end of the 5 year plan.

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M = -7 and it passes through the point (0,4)
Alla [95]

Answer:

Y = -7x + 4

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
2sin^2x - sinx - 3 = 0
e-lub [12.9K]
We have that
2sin²<span>x - sinx - 3 = 0
</span>
Let
A------> sin x
so
2A²-A-3=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solutions are
A=-1
A=1.5------> is not solution because sin x <span>can not be 1.5

the solution is
A=-1
therefore
sin x=-1
x=arc sin(-1)=-90</span>°

the answer is
sin x=-1
x=-90° or 270°

8 0
3 years ago
I need to have more or one answer
NeX [460]
I can’t see the pic sorry
5 0
2 years ago
Aisha is buying corn seed packs sold in boxes of 100. She has 400 packs, but she needs a total of 600
devlian [24]
That means she need to buy 2 packs of 100.
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