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AlexFokin [52]
3 years ago
15

What are the characteristics of the sorting and grouping options in Outlook? Check all that apply. Columns can be sorted by clic

king the column heading. Advanced View Settings include Group By and Sort settings. Messages can be grouped according to their content and type. When Show by Groups is selected, they can be collapsed for easy view. The current view can be saved as a new view under the Change View button.
Computers and Technology
2 answers:
kodGreya [7K]3 years ago
8 0

Answer:

its a,b,d, and e on edge 2020

Explanation:

i just got it right.

Rzqust [24]3 years ago
6 0

Answer: a b d e is right

Explanation:

just took it on edge 2021

You might be interested in
Write a function, sublist, that takes in a list of numbers as the parameter. In the function, use a while loop to return a subli
Alla [95]

Answer:

Following are the code to this question:

def sublist(l):#defining a method list sublist that accepts a list

   val=[]#defining an empty list

   x=0#defining x variable that store value 0

   while(x<len(l)):#defining loop that check x is lessthen list length  

       if(l[x]==5):#defining if block that checks list value equal to 5

           break#using break keyword  

       val.append(l[x])#add value in val list

       x+= 1#increment the value of x variable by 1

   return val#return val

l=[3,4,7,8,5,3,2]#defining list l

print(sublist(l))#using print method to call sublist method

Output:

[3, 4, 7, 8]

Explanation:

  • In the above python code, a method "sublist" is declared that accepts a list, inside the method an empty list "val" and an integer variable x is defined that stores "0"  value.
  • In the method, a while loop is declared that checks list length and define if block to checklist element value equal to "5". which the condition is true it will return before values.
  • In the last step, a list "l" is declared that holds value and used the print method to call sublist to prints its return value.
4 0
3 years ago
Which is the common name for a program that has no useful purpose, but attempts to spread itself to other systems and often dama
Maksim231197 [3]
Its know as a virus (a program created to spread and maliciously harm computers)
7 0
3 years ago
AYUDAAAA!!!!! URGENTE!!!!!!1<br> ¿para que sirve la "BIG DATA"?
Lisa [10]

Answer:

Big data is a field that treats ways to analyze, systematically extract information from, or otherwise deal with data sets that are too large or complex to be dealt with by traditional data-processing application software. ... Big data was originally associated with three key concepts: volume, variety, and velocity.

SPANISH TRANSLATION

Big data es un campo que trata formas de analizar, extraer sistemáticamente información de, o de otra manera tratar con conjuntos de datos que son demasiado grandes o complejos para ser manejados por el software tradicional de aplicación de procesamiento de datos. ... Big data se asoció originalmente con tres conceptos clave: volumen, variedad y velocidad.

7 0
2 years ago
A haiku is a three-line poem in which the first line contains five syllables, the second line contains seven syllables, and the
tankabanditka [31]

Answer:

Files :

server.c

client.c

Haiku msg : ( source internet )

Birds fly through the wind

The wind blows through the blue sky

Winds of change grow close

Explanation:

server.c

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#include <sys/socket.h>

#include <netinet/in.h>

// Here we've defined the PORT

#define PORT 5755

// This a out haiku_msg

const char haiku_msg[] = "Birds fly through the wind\nThe wind blows through the blue sky\nWinds of change grow close";

int main()

{

int server_fd, new_socket;

struct sockaddr_in address;

int addrlen = sizeof(address);

// Creating socket file descriptor

if ((server_fd = socket(AF_INET, SOCK_STREAM, 0)) == 0) {

perror("socket failed");

exit(EXIT_FAILURE);

}

address.sin_family = AF_INET;

address.sin_addr.s_addr = INADDR_ANY;

address.sin_port = htons(PORT);

if (bind(server_fd, (struct sockaddr*)&address, sizeof(address)) < 0) {

perror("bind failed");

exit(EXIT_FAILURE);

}

printf("haiku server started...\n\n");

if (listen(server_fd, 5) < 0) {

perror("listen");

exit(EXIT_FAILURE);

}

if ((new_socket = accept(server_fd, (struct sockaddr*)&address, (socklen_t*)&addrlen)) < 0) {

perror("accept");

exit(EXIT_FAILURE);

}

printf("\nClient connected to haiku server.\nsending msg.\n");

send(new_socket, haiku_msg, strlen(haiku_msg), 0);

printf("haiku sent to client.\n\n");

return 0;

}

client.c

#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

#include <string.h>

#include <arpa/inet.h>

#include <sys/socket.h>

#include <netinet/in.h>

// Here we have defined the PORT

#define PORT 5755

int main()

{

char buffer[1024] = "";

struct sockaddr_in address;

struct sockaddr_in serv_addr;

int sock = 0;

if ((sock = socket(AF_INET, SOCK_STREAM, 0)) < 0)

{

printf("\n Socket creation error \n");

return -1;

}

memset(&serv_addr, '0', sizeof(serv_addr));

serv_addr.sin_family = AF_INET;

serv_addr.sin_port = htons(PORT);

// Convert IPv4 and IPv6 addresses from text to binary form

if(inet_pton(AF_INET, "127.0.0.1", &serv_addr.sin_addr)<=0)

{

printf("\nInvalid address/ Address not supported \n");

return -1;

}

if (connect(sock, (struct sockaddr *)&serv_addr, sizeof(serv_addr)) < 0)

{

printf("\nConnection Failed \n");

return -1;

}

read( sock , buffer, 1024);

printf("\nMessage from server : \n%s\n\n",buffer );

return 0;

}

4 0
3 years ago
The mathematical constant Pi is an irrational number with value approximately 3.1415928... The precise value of this constant ca
tatiyna

Answer:

I am writing a Python program:

def approxPIsquared(error):

   previous = 8

   new_sum =0

   num = 3

   while (True):

       new_sum = (previous + (8 / (num ** 2)))

       if (new_sum - previous <= error):

           return new_sum

       previous = new_sum

       num+=2    

print(approxPIsquared(0.0001))

Explanation:

I will explain the above function line by line.

def approxPIsquared(error):  

This is the function definition of approxPlsSquared() method that takes error as its parameter and approximates constant Pi to within error.

previous = 8     new_sum =0      num = 3

These are variables. According to this formula:

Pi^2 = 8+8/3^2+8/5^2+8/7^2+8/9^2+...

Value of previous is set to 8 as the first value in the above formula is 8. previous holds the value of the previous sum when the sum is taken term by term. Value of new_sum is initialized to 0 because this variable holds the new value of the sum term by term. num is set to 3 to set the number in the denominator. If you see the 2nd term in above formula 8/3^2, here num = 3. At every iteration this value is incremented by 2 to add 2 to the denominator number just as the above formula has 5, 7 and 9 in denominator.

while (True):  This while loop keeps repeating itself and calculates the sum of the series term by term, until the difference between the value of new_sum and the previous is less than error. (error value is specified as input).

new_sum = (previous + (8 / (num ** 2)))  This statement represents the above given formula. The result of the sum is stored in new_sum at every iteration. Here ** represents num to the power 2 or you can say square of value of num.

if (new_sum - previous <= error):  This if condition checks if the difference between the new and previous sum is less than error. If this condition evaluates to true then the value of new_sum is returned. Otherwise continue computing the, sum term by term.

return new_sum  returns the value of new_sum when above IF condition evaluates to true

previous = new_sum  This statement sets the computed value of new_sum to the previous.

For example if the value of error is 0.0001 and  previous= 8 and new_sum contains the sum of a new term i.e. the sum of 8+8/3^2 = 8.88888... Then IF condition checks if the

new_sum-previous <= error

8.888888 - 8 = 0.8888888

This statement does not evaluate to true because 0.8888888... is not less than or equal to 0.0001

So return new_sum statement will not execute.

previous = new_sum statement executes and now value of precious becomes 8.888888...

Next   num+=2  statement executes which adds 2 to the value of num. The value of num was 3 and now it becomes 3+2 = 5.

After this while loop execute again computing the sum of next term using       new_sum = (previous + (8 / (num ** 2)))  

new_sum = 8.888888.. + (8/(5**2)))

This process goes on until the difference between the new_sum and the previous is less than error.

screenshot of the program and its output is attached.

6 0
3 years ago
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