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Dima020 [189]
3 years ago
6

The smallest unit of a spreadsheet, and it is formed by the intersection of a row and a column.

Computers and Technology
1 answer:
slega [8]3 years ago
5 0
The answer would be: B. Cell
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Write a single statement that assigns avg_sales with the average of num_sales1, num_sales2, and num_sales3.
sammy [17]

Answer:

Explanation:

try numpy:

import numpy as np

print(np.average([3, 4, 8]))

output:

5.0

3 0
3 years ago
When creating envelopes, how will you adjust the layout?
Burka [1]
It D because I hade this too so it is D
4 0
3 years ago
Read 2 more answers
What is the initial condition in this set of code?
marissa [1.9K]

Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.

The video above uses the example

{

d

y

d

x

=

cos

(

x

)

y

(

0

)

=

−

1

to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you  

y

=

sin

(

x

)

+

C

.

Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in  

0

for  

x

and  

−

1

for  

y

gives us  

−

1

=

C

, meaning that the particular solution must be  

y

=

sin

(

x

)

−

1

.

So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.

Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be  

y

-values. Higher-order equations might have an initial value for both  

y

and  

y

′

, for example.

Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.

Explanation:

5 0
3 years ago
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

5 0
3 years ago
You have just purchased a server with Windows Server 2016 Datacenter Edition installed. The server has 4 GB RAM, a 200 GB hard d
Elena L [17]

Answer:

a. Install more RAM

Explanation:

According to my research on information technology, I can say that based on the information provided within the question this server will not work for you purpose unless you install more RAM. This is because Hyper-V server's have a minimum requirement of 4gb, therefore if you want to run 2 servers you can divide all the resources you have since they are enough but not the RAM since you only have the bare minimum for one server. You need to add atleast 4 gb more of RAM.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0
4 years ago
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