Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
7hours > 75 minutes, 60 mins in a hr,
Answer:
x = 2.95
Step-by-step explanation:
<u>Step 1: Convert words into an expression</u>
0.45 plus 9x equals 27
0.45 + 9x = 27
<u>Step 2: Solve for x</u>
0.45 + 9x - 0.45 = 27 - 0.45
9x / 9 = 26.55 / 9
x = 2.95
Answer: x = 2.95
Answer:
14x - 8 = 22 + 20x
x = -5
Step-by-step explanation:
Let "the number" be represented by x
Take each part of the statement and translate into algebraic form
"14 times a number" 14x
"decreased By eight" -8
"is" =
"22 Increased by" 22 +
"20 times The same number" 20x
Put the equation together. Solve for x by isolating.
(
14x - 8 = 22 + 20x
14x - 8 - 20x = 22 + 20x - 20x Subtract 20x from both sides
-6x - 8 = 22
-6x - 8 + 8 = 22 + 8 Add 8 to both sides
-6x = 30
-6x ÷ -6 = 30 ÷ -6 Divide both sides by -6
x = -5
