<img src="https://tex.z-dn.net/?f=38%2B7%C2%B7%28x-3%29%3D9%C2%B7%28x%2B1%29" id="TexFormula1" title="38+7·(x-3)=9&middot

All categories

Mama L [17]

2 years ago

;(x+1)" alt="38+7·(x-3)=9·(x+1)" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

AnnZ [28]2 years ago

6 0

$38 + 7x - 21 = 9x + 9$

Combine like terms.

$17 + 7x = 9x + 9$

Eliminate a x.

$17 = 2x + 9$

$8 = 2x$

$x = 4$

ryzh [129]2 years ago

5 0

38 + 7x - 21 = 9x + 9

7x + 17 = 9x + 9

Subtract both sides 9

7x + 17 - 9 = 9x + 9 - 9

7x + 8 = 9x

Subtract sides 7x

7x - 7x + 8 = 9x - 7x

8 = 2x

Divide both sides by 2

8 ÷ 2 = 2x ÷ 2

x = 4

You might be interested in

The price of an item yesterday was 130. Today, the price fell to 91 . Find the percentage decrease.

Shalnov [3]

Answer:

30%

Step-by-step explanation:

130-91=39

39 / 130 =0.3

0.3x100=30

and you got the answer!

7 0

2 years ago

Read 2 more answers

What is the multiplicative rate of change of the exponential function represented in the table

stepan [7]

We are given the following data
x y
1 4.5
2 6.75
3 10.125
4 15.1875

To get the multiplicative rate of change, we pick out two pairs of data so,
MROC = 6.75/4.5 / (2 - 1)
MROC = 1.5

The answer is 1.5

4 0

2 years ago

Read 2 more answers

On tuesday bill bought nine posters. On wednesday half of all the posters that he had were destroyed. On thursday there were onl

Anettt [7]

(x+9)/2+=24
*2 I *2
x+9=48
-9 -9
x=39

4 0

3 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

Together, teammates Pedro and Ricky got 2682 base hits last season. Pedro had 282 more hits than Riley. How many hits did each p

pickupchik [31]

Pedro had 1482 hits and Riley had 1200 hits.

Step-by-step explanation:

Given,

Number of base hits = 2682

Let,

Number of Pedro's hits = x

Number of Riley's hits = y

According to given statement;

x+y=2682 Eqn 1

x = y+282 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$(y+282)+y=2682\\y+282+y=2682\\2y=2682-282\\2y=2400$

Dividing both sides by 2

$\frac{2y}{2}=\frac{2400}{2}\\y=1200$

Putting y=1200 in Eqn 2

$x=1200+282\\x=1482$

Pedro had 1482 hits and Riley had 1200 hits.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

4 0

3 years ago