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GarryVolchara [31]
3 years ago
13

Simplify the expression (x^19 times y^21) divided by (x^2 times y^6)^2

Mathematics
1 answer:
Lyrx [107]3 years ago
3 0

Answer:

x^{15}.y^{9}

Step-by-step explanation:

\frac{x^{19} . y^{21}}{(x^2. y^6)^2} \\\\Here\,\, exponent\,\, rules\,\, will\,\, be\,\, used.\\First\,\, multiply\,\, power\,\, of \,\,2\,\, with\,\, denominator \,\,exponents\\\\\frac{x^{19} . y^{21}}{x^4. y^{12}}\\If \,\, same\,\, bases\,\, are\,\, divided\,\, then\,\, their\,\, exponents\,\, are \,\,subtracted\,\,\\\\x^{19-4}.y^{21-12}\\\\x^{15}.y^{9}

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