All categories

3 years ago

Simplify the expression (x^19 times y^21) divided by (x^2 times y^6)^2

Mathematics

1 answer:

Lyrx [107]3 years ago

3 0

Answer:

$x^{15}.y^{9}$

Step-by-step explanation:

$\frac{x^{19} . y^{21}}{(x^2. y^6)^2} \\\\Here\,\, exponent\,\, rules\,\, will\,\, be\,\, used.\\First\,\, multiply\,\, power\,\, of \,\,2\,\, with\,\, denominator \,\,exponents\\\\\frac{x^{19} . y^{21}}{x^4. y^{12}}\\If \,\, same\,\, bases\,\, are\,\, divided\,\, then\,\, their\,\, exponents\,\, are \,\,subtracted\,\,\\\\x^{19-4}.y^{21-12}\\\\x^{15}.y^{9}$

You might be interested in

A 180 pound person is hanging onto a 15-foot rope. Assuming the rope is uniform and that it weighs 2 pound per foot, set up (but

aleksklad [387]

Answer:

The answer is "g= 32 FPS"

Step-by-step explanation:

Given value:

$mass = 180\\\\length= 15 \\\\\lambda = \frac{ mass}{ length} = 2 \ \text{pound per foot} \\\\\bold{Formula}\\\\ \to w \int_{a}^{b} F \cdot d \ dx = \int_{0}^{15} (2x+180) \ g \ dx$

by solving the value we get the value of g that is equal to 32.

4 0

2 years ago

Mrs. Balcon owes the dentist $342. She wants to have her payments taken from her checking account over the next 7 1/2 months. By

kiruha [24]

Answer:

$45.60 per month

Step-by-step explanation:

She owes the dentist $342.00

you take $342.00 divided by 7.5(the amount of months)

and get $45.60 per month

7 0

2 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

I really need help please

Iteru [2.4K]

Answer is C
Because 2 is your Y intercept and -1/2 means your going to move down 1 then move 2 to the right

7 0

2 years ago

Read 2 more answers

You have $10.00 and want to buy candy for $8.73. How much money will you have left over?

Viktor [21]

Answer:

$1.27

Step-by-step explanation:

You simply just need to subtract 10.00-8.73 to get your answer which is 1.27.

6 0

3 years ago

Read 2 more answers