1) x < 4 the answer is <span> Option C: x E(-infinity,4) (it is strict)
2) </span>2x +6 < 8, and <span>2x < 8 - 6 = 2, and x<2/2=1
the answer is </span>
<span>D. x E (-infinity, 1)
</span>3) <span>X greater than or equal to 8 and x < - 4
</span>X greater than 8 means x ≥ 8
so we have x ≥ 8 and <span> x < - 4
so the answer is </span>
<span>B. x E (-4,8]
</span> 4)
7 > x + 6 or x -2 greater than or equal to 3,
<span>7 > x + 6 or x -2 ≥ 3
</span>
<span>7 -6> x, and 1>x
</span>
x -2 ≥ 3 x<span>≥ 3+2=5
finally
</span>x<1 and x≥5
the answer is
<span>C.x E (1,5]
5)
</span>
|x+3| > 12,
|x+3| = { -(x+3) if <span>x+3<0 or </span><span>(x+3) if </span><span>x+3>0}</span>
so, it is -(x+3)>12 is equivalent to (x+3)< -12 or (x+3)>12
the answer is
<span>B. x + 3 > 12 or x + 3 <-12</span>
Answer:
(Measure ) L+W : 11 and 8 inches.
These L + W measures are of each triangle and when either halved as proven below will show (A): 44inch^2
Step-by-step explanation:
Two congruent triangles of 44 sq inch = base 8 height 11
or base 11 height 8
Finding that both numbers find the same area.
Note for future areas either measure for triangle base + height
8 x 11 or 11 x 8 = 88 when halved its the same answer.
where 7 x 10 = 35
13 x 10 = 65
and so on;
No other number multiplies its length and height to show 44
One quarter equals 25 cents so if you add 25 four times it will equal one dollar
Answer:
Step-by-step explanation:
The total amount Rita spent is ...
(18.54x +23) +(25) = 18.54x +48 . . . total spent
__
When x=2, that is approximately ...
(18.5)(2) + 48 = 37 +48 = (40 -3) +(50 -2) = (40 +50) -(3 +2) = 90 -5 = 85
Rita spent about $85 if she bought 2 items.
_____
<em>Additional comment</em>
Estimation is often done using 1 significant figure. In this case, that would mean rounding the equation to 20x+50, so it would give a value of 90 when x=2.
An additional task when estimating is to estimate the error in the estimate. Here, using 20x+50 has an error of approximately 1.5x+2 (too high), so the error for 2 items will be about (1.5(2)+2) = 5. That is, the estimate of 90 is approximately 5 too high. Even this estimate has a remaining small error of 0.04x (too low).
