Let g (x) = -1/2x + 6 and h (x) = g (x) -3 which statement describes the graph of h (x)?

For each of the bookcases a woodworker is building, she

Naya [18.7K]

35x100 hours = $3500+$65= $3565 for 100 hours of work and materials.

7 0

3 years ago

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Write and simplify the equation you would use to solve the problem below.

Taya2010 [7]

12s + 5 = 77
12s = 77 - 5 = 72
s = 72/12
s = 6 ...//

Ans = C ... 12x + 5 = 77 ...

7 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

3 years ago

A video game has the following formula: For every 1,333 in attack power, you gain 3 levels. You get one bonus star per every 38

aleksley [76]

Answer:

Rounded to a whole number, the player has 12 bonus stars.

Step-by-step explanation:

Since the video game establishes that for every 1,333 points of attack power 3 levels are gained, and that the player has a total of 0.21 million attack points, to determine the number of levels that player has it is necessary to perform the following calculation :

0.21 million = 210,000

210,000 / 1,333 x 3 = Levels

472.6 = Levels

Now, every 38 levels, the game awards a bonus star. To determine the amount of bonus stars that the player has, the following division must be made:

472.6 / 38 = X

12.43 = X

Thus, rounded to a whole number, the player has 12 bonus stars.

7 0

3 years ago

Find the volume of the sphere

madam [21]

Answer:

sphere volume = 3052.1 in³

Step-by-step explanation:

sphere volume = 4/3πr³ = 4/3(3.14)(9³) = 3052.1 in³

6 0

3 years ago