All categories

3 years ago

The sum of 2 number is 42 and when you switch the order the difference is 5

1 answer:

4 0

So, x + y = 42 and y - x = 5;
Then, y = x + 5;
Finally, x + x + 5 = 42;
2x + 5 = 42;
2x = 37;
x = 18.5;
y = 18.5 + 5;
y = 23.5;

You might be interested in

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

2 years ago

Calculate the area of the square shown on the xy-plane in the diagram.

natka813 [3]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

4 = 32x

inn [45]

Answer:

x=0.125

Step-by-step explanation:

4/32=0.125

4 0

3 years ago

What is the solution to the inequality? −6x+5>−1

Bogdan [553]

Answer:

$\boxed{x$

Step-by-step explanation:

$-6x+5>-1\qquad\text{subtract 5 from both sides}\\\\-6x>-6\qquad\text{change the signs}\\\\6x$

3 0

3 years ago

There are 50 cupcakes and 160 cookies to be sold at the school bake sale. What is the greatest number of packages of baked items

Sav [38]

The greatest number of packages of baked items that can be sold is 10

Solution:

Given that there are 50 cupcakes and 160 cookies to be sold at the school bake sale

To find: greatest number of packages of baked items that can be sold

Each package has the same number of cupcakes and same number of cookies with none left over

So, we have to find the greatest common factor of 50 and 160

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor.

Greatest common factor of 50 and 160:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 160 are: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, 160

Then the greatest common factor is 10

So the greatest number of packages sold is 10

Each package will contain:

Given that there 50 cupcakes and 160 cookies

Number of cupcakes in 1 package:

$\rightarrow \frac{50}{10} = 5$

Number of cookies in 1 package:

$\rightarrow \frac{160}{10} = 16$

So each package has the same number of cupcakes and same number of cookies with none left over

7 0

4 years ago