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3 years ago

Which of the following sets of points are vertices of a right triangle?

Mathematics

1 answer:

grandymaker [24]3 years ago

3 0

Please find the picture for your triangle.
We know, area of a ∆ = 1/2 × base × height
Here, base = ( 1 + 7 ) units = 8 units
Height = ( 7 - 1 ) units = 6 units
Therefore, area of the ∆
= (1/2 × 8 × 6) square units
= 24 square units.

Answer:

24 square units

Hope you can get an idea from it.

Carry on learning.

Doubt clarification - use comment section.

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Cameron and his children went into a movie theater where they sell drinks for $6 each and candies for $5 each. Cameron has $100

Pepsi [2]

Answer:

Cameron could buy 4 drinks and 15 candies

5 0

3 years ago

Simplify the following expression:

nalin [4]

-2/2 I think probably

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3 years ago

Write an expression equivalent to (7x + 5) - (3x - 5)

KiRa [710]

Answer:

= 2(2x + 5)

Step-by-step explanation:

Given that:

= (7x + 5) - (3x - 5)

By simplifying

"-" sign before bracket will alter the inner signs

= 7x + 5 - 3x + 5

Adding like terms

= 4x + 10

By taking 2 common we get:

= 2(2x + 5)

i hope it will help you!

6 0

3 years ago

Alec pours the same amount of soup into three balls he used 4 cups of soup how much soup is in each bowl

Ugo [173]

For this question you would need to do 4 divided by 3. The answer would be 1.3 cup(s) would be in each bowl.

Hope that helps!!

7 0

3 years ago

Solve the polynomial inequality x^2-3x-10>0

djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0

3 years ago