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Morgarella [4.7K]
3 years ago
9

Five million ninety thousand thirty nine​

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

5,090,039

Step-by-step explanation:

Just separate them, do them one at a time and add them all together

5,000,000

     90,000

+          039

___________

Hope this helps

~R3V0

Leya [2.2K]3 years ago
3 0

Answer:

5,090,039

Step-by-step explanation:

Are you trying to number it out?

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The quotient of a and b
S_A_V [24]
Answer: take the first digit of a and divide it by b

Step-by-step explanation: and that should give you your answer and if not please feel free to mesage me.
8 0
2 years ago
Which does the P stand for in the surface area of prisms formula?
Sidana [21]

Answer:

A

Step-by-step explanation:

perimeter of the base...

7 0
3 years ago
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
What is 18% of 65? (I will give brainliest!)
Anettt [7]

Answer:

11.7

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
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