The area of the square is 9 in^2
The side of a square is the square root of the area.
Side of square = √9 = 3 inches.
The side of the square is the diameter of the inscribed circle.
Circumference of a circle is PI x diameter.
Circumference of inscribed circle = 3.14 x 3 = 9.42 inches
The diameter for the circumscribed circle would be the diagonal of the square which is 3√2 = ( Side length x √2) ≈ 4.2426
The circumference = 3.14 x 3√2 = 13.321
Find the ratio between the two circles:
Circumscribed / inscribed =
13.321 / 9.42 = 1.41
Answer:
3.66666666667
or
3.67(rounded to the nearest tenth)
Step-by-step explanation:
2x 1/2 x3 2/3 = 3.66666666667
<em>Ace Carlos</em>
<em>Developer</em>
Answer:
It's the first one.
hope it helps :)
Step-by-step explanation:
<h3><u>Question</u> :-</h3>
Is (x-2) is a factor of x³-3x²-x +7 –
<h3><u>Explanation</u> :-</h3>
We are given –
- Polynomial function, P(x) = x³-3x²-x +7
- In order to check if x - 2 is a factor of x³-3x²-x +7 or not, we must show that P(2) = 0.





Now Put x = 2 into the polynomial –





- Since the value of the polynomial function st x = 2 is not Zero (0). Henceforth, ( x - 2) is a factor of x³-3x²-x +7.
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Add 't' to both sides. t+r=s
Step-by-step explanation: