Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
Better hearing and better sound censory
i think anyways
Answer:
68°
Step-by-step explanation:
As BA⊥BD, so ∠ABD = 90°
also, ∠ABD = ∠CBD + ∠ABC
⇒ 90° = 4x + 52° + 8x - 10°
⇒ 12x = 48°
⇒ x = 4°
now,
∠CBD = 4x + 52°
= 4(4°) + 52°
= 68°
A negative number * another negative number gives a positive value
A positive number * another positive number also gives a positive value
The solutions are -4, 4
Hope this helps :)
Answer:
yes great job!
Step-by-step explanation: