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MrRissso [65]
3 years ago
6

Describe and compare protraction and retraction

Mathematics
1 answer:
disa [49]3 years ago
4 0

Answer:

Protraction and retraction are the movements of the mandibule. <em>Protraction is when the lower mandibule is pushed forward and retraction is when the lower jaw is pulled backward. </em>You can see in the image I added the example of these movements.

I hope you find this information useful and interesting! Good luck!

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3/8 of students in school ride the bus, what percent does not
Stells [14]
The answer is going to be 87.5%
6 0
3 years ago
I will give brainliest. Combine the like terms to create an equivalent expression: −5j+(−2j)+3
neonofarm [45]

Answer:

-7j +3

Step-by-step explanation:

-5j -2j +3

-7j +3

like terms are combined. combine the js

8 0
3 years ago
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Which of the following best describes the solution to the system of equations below?
OverLord2011 [107]

Answer: OPTION A

Step-by-step explanation:

The equation of the line in slope-intercept form is:

y=mx+b

Where m is the slope and b the y-intercept.

Solve for y from each equation:

\left \{ {{5y=-4x+7} \atop {10y=-8x+14}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-8}{10}x+\frac{14}{10}}} \right.\\\\\left \{ {{y=\frac{-4}{5}x+\frac{7}{5}} \atop {y=\frac{-4}{5}x+\frac{7}{5}}} \right.

As you can see the slope and the y-intercept of each equation are equal, this means that both are the exact same line. Therefore, you can conclude that the system has infinitely many solutions.

3 0
3 years ago
9. Find the area of the figure to the right.<br> area<br> 14 in
zlopas [31]

Answer:

1. 200 in.^2

2.

Step-by-step explanation:

1. Area of a trapezium=1/2(a+b)height

a=14 in.

b=20 in.+6 in. = 26 in.

height= ?

height can be gotten by using

formula : Soh Cah Toa

Toa is tangent∆= opposite/ adjacent

∆ = 60°

opp=? adj=6 in.

Tan 60° =opp/6 in.

Tan 60° = 1.732

1.732= opp/ 6 in.

opp=1.732*6 in.

opp = 10.392 approximately= 10 in.

Area of trapezium= 1/2*(14+26)*10(in.^2)

Area of trapezium= 1/2*40*10

= 1/2*400

= 200 in.^2 .

2. Area of triangle= 1/2* base* height

for first triangle =

base=4m

height =15m

Area: 1/2*4*15 ,1/2*60= 30m^2

second triangle =

base:?

height: 15m

using Pythagorean theorem;

hyp^2 = opposite ^2 + adjacent ^2

17^2 = 15^2 + adj^2

289= 225 + adj^2

adj^2 = 289-225= 64

square root

adj = 8m

area of second triangle : 1/2*8*15

: 1/2*120 :60m^2

total area: 30 m^2 +60m^2

==90 m^2

8 0
3 years ago
Recall what you know about similarity. If circle B is similar to circle A, what must exist?
Arlecino [84]

Answer:

circle a and circle b must exist

Step-by-step explanation:is circle a and circle b did not exist this question would not be one

7 0
3 years ago
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