For A, you wanna look at $350 and $750 and find out how much her pay increased from 2010 to 2014.
For B, you want to create an equation (math problem) <span>to represent the fees that Sarah charges each year that would be reliant to your answer for part A. Hope this helps!
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Answer:
See below
Step-by-step explanation:
Both horses travel 0 miles in 0 minutes. We can see this on the graph where both lines start at the 0 in the bottom left corner. For the purpose of writing the equations this also shows us that the y-intercept is 0. In a slope-intercept equation, y=mx+b, that number is the b. b is zero in both equations, so we don't need to write anything for that.
For horse A, we can see on the graph that at 4 minutes, horse A has traveled 1 mile. Also, confirming this rate, at 8 minutes, it went 2 miles. This will help us find the rate. The rate will be the number we fill in for the m in the y=mx+b equation. Horse A goes 1mile every 4 minutes. That is a rate of 1/4 miles per minute. So Horse A's equation will be
y = (1/4)x You can make it more *intuitive* possibly by using m for miles and t for time instead, like this:
m = (1/4)t
Horse B is a little bit faster, and you can see this bc the line is a little bit steeper. It goes 2 miles in 5 minutes (confirm you can see it goes 4 miles in 10 minutes)
So Horse B's equation is
y = (2/5)x
or miles = (2/5)time
Mathematically, the equations are the same whether you use x,y or m,t
If Horse A runs for 12 minutes then it will run
miles = (1/4)minutes
miles = (1/4)(12)
miles = 3
If Horse B runs for 12 minutes, then it will run
miles = (2/5)minutes
miles = (2/5)12
miles = 4.8
p= 610/62, or 9.84 hope this hopes (5)
E=mc2 (5-2)x+99.03 with the addition of beans
Answer:
I need to see the whole question but I believe you just add the numbers
