280,706 is the standard form
Answer:
Step-by-step explanation:
Hi there,
The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.
To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.
With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.
Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!
thanks,
Answer:
Explanation:
<u>1. Calculate the monthly interest owed during year 1</u>
<u />
- <em>Interest for first year: 8%</em>
- The monthly rate is the yearly rate divided by 12: 8% / 12 = 0.08/12
- The monthly interest owed is the monthly rate times the balance: (0.08/12)×$1,800 = $12.00
<u>2. Calculate the monthly interest owed during year 2</u>
<u />
- <em>Interest for second year: 23%</em>
- The montly rate is the yearly rate divided by 12: 23% / 12 = 0.23/12
- The monthly interest owed is the monthly rate times the balance: (0.23/12)×$1,800 = $34.50
<u>3. Calculate the difference</u>
- Difference in the monthly interest owed during year 1 and year 2 = $34.50 - $12.00 = $22.50
Hence, the answer is the option c) $22.50
Answer:
1/6
Step-by-step explanation:
The gradient of the line segment is the same as slope
m = (y2-y1)/(x2-x1)
= ( -4 - -5)/( 2 - -4)
= (-4+5)/( 2 +4)
1/6
