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3 years ago

Is this statement true or false? You can apply only one of these at a time: underline, bold, or italics. true false

Computers and Technology

1 answer:

Lelechka [254]3 years ago

8 0

I think false not sure but let other people help u answer and u can decide

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You view a portion of a document on the screen through a ____.

alekssr [168]

You view a portion of a document on the screen through a C. Document window

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3 years ago

1. I write about my travel experiences on my own personal ____?

alekssr [168]

Answer:

Hello There!!

Explanation:

1.blog

2.laptop

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3 years ago

What is operating system

iren [92.7K]

Answer:

It's simply a software that runs a computer's basic tasks, or functions, such as scheduling, running applications, and controlling peripherals.

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3 years ago

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The accounting department moved its network-attached printer from one side of the office to a more centralized location, making

Blababa [14]

Answer:

The cable run connecting the new keystone jack to the patch panel is bad.

The patch panel connector for the new location's cable run is not connected to a switch.

Explanation:

The cable run connecting the new keystone jack to the patch panel is bad.

The patch panel connector for the new location's cable run is not connected to a switch.

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3 years ago

Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc

Kipish [7]

Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, $t_{A} = 100 ps$

$t_{A} = 150 ps$

No. of cycles per instructions, $n_{A} = 2.0$

$n_{B} = 1.0$

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, $f_{A}$ = 2.0 I

CPU clock cycle, $f_{B}$ = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = $CPU clock cycle\times clock time$

$T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps$

$T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps$

Thus B is faster than A

Now,

$\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}$

$\frac{Performance of A}{Performance of B} = \frac{200}{150}$

Performance of B is 1.33 times that of A

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3 years ago

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