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dedylja [7]
3 years ago
11

If x+1 and x-1 are the factors of the polynomial ax^3 + x^2 - 2x +b,find the values of a and b

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

The polynomial remainder theorem says that dividing a polynomial p(x) by x-c leaves a remainder of p(c)=0 if x-c is a factor of p(x). In this case, check c=-1 and c=1.

a(-1)^3+(-1)^2-2(-1)+b=-a+b+3=0

a(1)^3+(1)^2-2(1)+b=a+b-1=0

From the first equation,

-a+b+3=0\implies a=b+3

and substituting into the second gives

(b+3)+b-1=0\implies2b+2=0\implies b=-1\implies a=2

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Answer:

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Step-by-step explanation:

Given

- 3 | 2x + 6 | = - 12 ( divide both sides by - 3 )

| 2x + 6 | = 4

The absolute value always returns a positive value, but the expression inside can be positive or negative, that is

2x + 6 = 4 ( subtract 6 from both sides )

2x = - 2 ( divide both sides by 2 )

x = - 1

OR

- (2x + 6) = 4 ← distribute left side

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- 2x = 10 ( divide both sides by - 2 )

x = - 5

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

x = - 1 → - 3| - 2 + 6 | = - 3 | 4 | = - 3 × 4 = - 12 ← True

x = - 5 → - 3 | - 10 + 6 | = - 3 | - 4 | = - 3 × 4 = - 12 ← True

Thus x = - 5 and x = - 1 are the solutions

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4 years ago
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Lelu [443]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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