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bogdanovich [222]
2 years ago
12

A box contains 18 yellow, 24 green and 28 red jelly beans. If 12 jelly beans are selected at random, what is the probability tha

t:
Mathematics
1 answer:
Nana76 [90]2 years ago
4 0

Yellow: 25.71% chance of you grabbing a yellow jelly bean

Green:34.29% chance of you grabbing a green jelly bean

Red: 40% chance of you grabbing a red  jelly bean

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Every seventh-grade student at Martin Middle School takes one world language class.
koban [17]

Answer:

s = 180

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s is the total number of seventh-grade students

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2 years ago
Vavilen inflated a huge balloon in 19 minutes. Then he poked a hole in the balloon so that it slowly leaked air out until it was
kaheart [24]

Considering balloon to be an spherical object

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After 19 minutes ,If radius of balloon changes from r to R, the Volume changes from V to V'.

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As given,rate at which the air leaked out of the balloon (in liters of air per minute) was half of the rate at which Vavilen inflated the balloon.

Also, \frac{dR}{dt}=2 \times \frac{dr}{dt}

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Time taken by the balloon to deflate = 38 minutes

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So, we can't predict at which rate balloon is deflating or inflating.Apart from the statement given in Question:   \frac{dR}{dt}=2 \times \frac{dr}{dt}

7 0
3 years ago
Read 2 more answers
How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.
kifflom [539]
<h2><u>QUADRATIC EQUATION</u></h2>

<h2>\mathbb{ANSWER:}</h2>
  • \bold{x = 0.8 \: } \:  \sf \:  {\color{grey}or} \:  \:  \:  \bold{ x=  \frac{4}{5} } \\

  • \bold{x =  - 6}

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

\bold{Given \:  Equation: \color{brown} 5x²+26x-24=0}

First, add 24 to both sides.

  • \bold{5x²+26x-24 - \purple{ 24} = 0 +  \purple{24}}

  • \bold{ \implies \: 5x²+26x = 24 }

Since the coefficient of 5x² is 5, divide both sides by 5.

  • \bold{ \frac{5 {x}^{2} + 26x }{5} =  \frac{24}{5}  } \\

  • \bold{ \implies \:  {x}^{2} +  \frac{26}{5} x =  \frac{24}{5}  } \\

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

  • \bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  \purple{169}}{ \purple{25}}=  \frac{24}{5}    +  \frac{ \purple{169}}{ \purple{25}} } \\

  • \bold{ \implies \:\bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  169}{ {25}}=  \frac{289}{25}  } } \\

Factor the left side.

  • \bold{(x +  \frac{13}{5} ) {}^{2} =  \frac{289}{25}  } \\

Take square root.

  • \bold{x +  \frac{13}{5} = ±  \:  \sqrt{ \frac{289}{25}  }} \\

Then, add (-13)/5 to both sides.

  • \bold{x +  \frac{13}{5} +  \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \:      \sqrt{ \frac{289}{25}}} \\

  • \bold{  \: x =  \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\

  • \implies \: \underline{ \boxed{ \bold{   \frac{4}{5}  } \sf  \:  \: or \:  \:  \bold{ x =  - 6}}} \\

_______________❖_______________

3 0
3 years ago
Read 2 more answers
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