A box contains 18 yellow, 24 green and 28 red jelly beans. If 12 jelly beans are selected at random, what is the probability tha
1 answer:
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Answer: i know this is way late, but it’s 48
Step-by-step explanation:
Since point A is the separation of BE, both sides of the separation are equivalent, the are congruent. Since AB=24, you add 24+24 to get 48.
(I also just answered this question on homework and got it right, this is just how I did it.)
