Answer:
-2 degrees Celsius.
Step-by-step explanation:
15 - 17 = -2
Answer:
The arc length is 
Step-by-step explanation:
Given that,
The given curve between the specified points is

The points from
to 
We need to calculate the value of 
Using given equation

On differentiating w.r.to y




We need to calculate the arc length
Using formula of arc length

Put the value into the formula








Put the limits


Hence, The arc length is 
In the first digit, there are 6 possibilities. In the second, there are 5, because you can't use the digit you used before. In the third, there are 4, and in the fourth, there are 3. So,
6*5*4*3=360
There are 360 different possible four-digit numbers
The equation of line T is 2x - y = 7 ⇒ (6x - 3y = 21)
Step-by-step explanation:
A dilation is a transformation that produces an image that is the same shape as the original, but is a different size
- If the equation of a line is ax + by = k is dilated, with center origin and scale factor k, then the equation of the image of the line is kax + kby = kc
- The line and its image are parallel
- The coordinates of a general point on the image is (kx , ky)
Line L is mapped onto the line T by a dilation centered at the origin and a scale factor of 3.
That means lint T is the image of line L after dilation
∵ The equation of line L is 2x - y = 7
∵ Line L is dilated by scale factor 3 and centered at origin
- That means multiply the equation of line L by 3 to find the
equation of line t
∵ Line T is the image of line L after dilation
∴ The equation of line T is (3)(2x) - (3)(y) = (3)(7)
∴ The equation of line T is 6x - 3y = 21
<em>Very important note:</em>
The equation of line T is the same with equation of line L but multiplied by the scale factor 3 ⇒ L and T are coincide lines (same line)
That means the equation of lines T and L is 2x - y = 7
The equation of line T is 2x - y = 7 ⇒ (6x - 3y = 21)
Learn more:
You can learn more about dilation in brainly.com/question/2480897
#LearnwithBrainly
Answer:
numbwer 8 is 44.04
Step-by-step explanation:
plz put brainliest