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ratelena [41]
3 years ago
10

Please help! I get how to do the first part I just don't get how to do the second part.

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0

9514 1404 393

Answer:

  WX = 33

  (x, y) = (2, 10)

Step-by-step explanation:

The hash marks tell you WX is a midline, so has the measure of the average of the two bases.

  WX = (PQ +SR)/2 = (27 +39)/2 = 66/2

  WX = 33

__

The hash marks also tell you ...

  PW = WS

  y +4x = 18 . . . . . . substitute the given expressions

and also

  QX = XR

  2y +x = 22 . . . . . substitute the given expressions

__

If you solve the first equation for y, you get ...

  y = 18 -4x

Substituting that into the second equation gives ...

  2(18-4x) +x = 22

  36 -7x = 22 . . . . . . . simplify

  14 = 7x . . . . . . . . . . . add 7x-22 to both sides

  2 = x . . . . . . . . . . . . divide by 7

  y = 18 -4(2) = 10 . . . find y using the above relation

The values of x and y are 2 and 10, respectively.

__

My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.

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ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

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