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ratelena [41]
3 years ago
10

Please help! I get how to do the first part I just don't get how to do the second part.

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0

9514 1404 393

Answer:

  WX = 33

  (x, y) = (2, 10)

Step-by-step explanation:

The hash marks tell you WX is a midline, so has the measure of the average of the two bases.

  WX = (PQ +SR)/2 = (27 +39)/2 = 66/2

  WX = 33

__

The hash marks also tell you ...

  PW = WS

  y +4x = 18 . . . . . . substitute the given expressions

and also

  QX = XR

  2y +x = 22 . . . . . substitute the given expressions

__

If you solve the first equation for y, you get ...

  y = 18 -4x

Substituting that into the second equation gives ...

  2(18-4x) +x = 22

  36 -7x = 22 . . . . . . . simplify

  14 = 7x . . . . . . . . . . . add 7x-22 to both sides

  2 = x . . . . . . . . . . . . divide by 7

  y = 18 -4(2) = 10 . . . find y using the above relation

The values of x and y are 2 and 10, respectively.

__

My favorite "quick and dirty" way to solve a set of linear equations is using a graphing calculator. It works well for integer solutions.

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4 x 7 = 28 - 30 = -2. His change is 2 dollars.
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3 years ago
p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

\frac{p}{q {r}^{2} }  = k

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

\frac{200}{18}  = k

\frac{100}{9}  = k

Now, since we know our constant, let find p.

\frac{p}{q {r}^{2} }  =  \frac{100}{9}

Q is 5, and r is 2.

\frac{p}{5( {2}^{2}) }  =  \frac{100}{9}

\frac{p}{20}  =  \frac{100}{9}

p =  \frac{2000}{9}

3 0
1 year ago
I’m trying to prove this but I’m stuck... :( <br><br> Can someone help ?
Tom [10]
I can help, but what are you exactly trying to do here?
7 0
2 years ago
What is<br> 3Vsquare27 + v64square -2
serg [7]

Answer:

Step-by-step explanation:

I think you are inventing symbols, which turns your question into a guessing game. You are better off describing the math symbols in words. Or post a picture.

I’m guessing that the math expression is ∛27 + √64² - 2 = 3 + 64 - 2 = 65

8 0
3 years ago
Which congruence theorems can be used to prove EFG congruent to JHG
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3 years ago
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