The rate of the slower jet is 672 miles per hour.
The rate of the slower jet is 752 miles per hour.
<h3>How to find the rate of the jets?</h3>
Two jets leave an air base at the same time and travel in opposite directions.
One jet travels 80 mi/h faster than the other.
let
x = rate of the slower jet
faster jet = 80 + x
Therefore,
rate = distance / time
The two jets are 11392 miles apart.
(80 + x)8 + 8x = 11392
640 + 8x + 8x = 11392
640 + 16x = 11392
16x = 11392 - 640
16x = 10752
divide both sides by 16
x = 10752 / 16
x = 672 miles per hour
rate of the faster jet = 80 + 672 = 752 miles per hour
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Answer:
25 acute
Step-by-step explanation:
Answer:x=13
Step-by-step explanation:
Since they are both corresponding angles you can create the equation
5x+21=86
Subtract 21 from each side
5x=65
Divide each side by 5
X=13
3 sets of the 4 inch ribbon is 12,
10 sets of the 4 inch ribbon is 40
