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saveliy_v [14]
3 years ago
6

Which of the following numbers is not in the interval (3, 9]? 3.14 9 3 7

Mathematics
1 answer:
ladessa [460]3 years ago
3 0
3.14 at blar blathbbn high ghhj
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You have been asked to develop a composite measure of the quality of life on your campus.
Shkiper50 [21]

The social indicators that can be used to know the quality of life in campus are the number of hours spent in school, extra curricular activities, etc.

<h3>What are social indicators?</h3>

It should be noted that social indicators are used to monitor the social system.

The social indicators that can be used to know the quality of life in campus are the number of hours spent in school, extra curricular activities, etc. They're important to assess ones social life.

In conclusion, after necessary data has been collected m, a research can be made to know how the quality of life is affected by the data.

Learn more about indicators on:

brainly.com/question/485822

5 0
2 years ago
F(x) = 9x - x2 + 3x<br> F(1) =
mojhsa [17]

Answer:

f(1) = 10

Step-by-step explanation:

Here you can just replace any x with 1.

f(1) = 9(1) - (1)2 + 3(1)

4 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!!!!!!
brilliants [131]

Answer: P=47 inches

Step-by-step explanation:

First, you have to find the other side lengths. Two of the sides are equal to 20 because this is a rectangle. The first blank would be 20 because 20 times the other side length is equal to 70. Then you would divide 70 by 20 which would equal x. x would equal 3.5 in. Then the perimeter would be:

2(20)+2(3.5)=P

P=47 inches

7 0
3 years ago
Please Help URGENT!!
AlekseyPX
Y + 79 + 37 = 180
y + 116 = 180
y = 64
3 0
3 years ago
Read 2 more answers
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
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