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pentagon [3]
2 years ago
15

Work out the lengths of sides a and b. Give your answers to 1 decimals place. (Pythagoras theoram

Mathematics
1 answer:
Simora [160]2 years ago
8 0

Step-by-step explanation:

h²=o²+a²

a²=8²+5²

a²=64+25

a²=89

a=√89

a=9.433

To one decimal place it is 9.4

for b,

h²=o²+a²

17²=b²+12²

289=b²+144

289-144=b²

145=b²

b=√145

b=12.041

To one decimal place it is 12.0

You might be interested in
Write an equation for the vertical line that contains point E(-12, 7). Is anybody able to help?
BigorU [14]

Answer:

x = -12

Step-by-step explanation:

Vertical lines take the form of x = something and horizontal lines take the form of y = something

Why is this? Notice that whenever you make a horizontal line on a graph and select virtually any point that's on that line, all of the points you pick will have the same y value. Try to imagine the same thing with a vertical line, are the results the same?

So the line x = -12 (we got -12 from the coordinate that was given to us on the question prompt) is a vertical line that passes through virtually all possible y values (from positive infinity to negative infinity, or vice-versa) which means that the question prompt having given us the y value was negligible.

Good luck!

5 0
3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 1
Nuetrik [128]

Answer:

attached

Step-by-step explanation:

attached

Download docx
8 0
3 years ago
I need to know x . if you could also explain that would be nice
defon

Answer:

x = 7.5

Step-by-step explanation:

Since the midsegment and the third segment of the triangle are parallel to each other, therefore,

\frac{8 + 10}{8} = \frac{6 + x}{6}

\frac{18}{8} = \frac{6 + x}{6}

\frac{9}{4} = \frac{6 + x}{6}

Cross multiply

9*6 = 4(6 + x)

54 = 24 + 4x

Subtract 24 from each side

54 - 24 = 4x

30 = 4x

Divide both sides by 4

30/4 = x

7.5 = x

x = 7.5

4 0
3 years ago
The point (4, 2) is reflected over a line to
IrinaK [193]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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