A = -2
b = 4
c = -3
They are the coefficients to the terms in the equation<span />
Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055
For this case we have the following equations:
y = 0.55x + 175
y = 0.45x + 200
We equate both equations:
0.55x + 175 = 0.45x + 200
We clear the value of x:
0.55x - 0.45x = 200 - 175
0.10x = 25
x = 250 miles
Answer:
A number of thousands driven that would make the two reimbursement packages equal is:
x = 250 miles