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dem82 [27]
3 years ago
7

The figure below is not drawn to scale. ABCD is a square. ACF and DCE are straight lines. Find ECF​

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

<ECF = 45 degrees

Step-by-step explanation:

If ABCD is a square, then the diagonal AC divides angle <C and angle <A  in two equal parts. Angles A and C are also 90 degrees each due to the act that the figure is a square. Therefore their bisection would render 90/2 = 45 degrees.

Notice as well that angle <ECF is opposite by the vertex to one of these 45 degree angles, and then it must measure the same amount (45 degrees).

So, <ECF = 45 degrees

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Answer:

Period=6

Step-by-step explanation:

Given:

t=1cos(1.05h)+37

Using acos(bx-c)+d to find the period of the given function

amplitude= a

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phase shift=c (positive is to the left)

vertical shift=d

comparing with t=1cos(1.05h)+37, we get

a=1

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