Carmen simplifies the expression (4y+ 8x+ 6)+ 25+(4x+ 6y+ 7). The coefficient of the variable y in her simplified answer is

Mathematics

2 answers:

Mademuasel [1]2 years ago

7 0

Answer:

OS THE 10 IS C IM CHECK AND IS CORRECT

alexandr1967 [171]2 years ago

6 0

The coefficient of 'y' in her simplified answer is 10.

You might be interested in

2. What is 9 squared. <br> a. 3<br> b. 81<br> C. 18<br> O d. 11

vitfil [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU <3

andrew11 [14]

Answer:

1. new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16

3. The new area is 1/9 of the original area.

Step-by-step explanation:

1. side length1 = x

side length2 = y

2x + 2y = perimeter

2(4x) + 2(4)y = new perimeter

8x + 8y = new perimeter

new perimeter = 4 times the old perimeter

2. The area will go up by a factor of 16. This is because the area formula has them being multiplied together and thus it will make the area go up by that much.

3. Let the length of the rectangle be x

Let width of rectangle be y

Area of rectangle = L*W

Now Each side length of the rectangle is multiplied by 1/3

So, new area = (1/3)L * (1/3)W

=(1/9)LW

So, the new area is 1/9 of the original area.

7 0

3 years ago

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$