he magician starts with the birthday boy and moves clockwise, passing out 100100100100 pieces of paper numbered 1111 through 100100100100. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 100100100100, and chooses the volunteer with that number.
Method2: The magician starts with the birthday boy and moves counter-clockwise, passing out 75757575 pieces of paper numbered 1111 through 75757575. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 75757575, and chooses the volunteer with that number.
Method 3\: The magician starts with the birthday boy and moves clockwise, passing out 30303030 pieces of paper numbered 1111 through 30303030. He cycles around the circle until all the pieces are distributed. He gives #1111 to the birthday boy, #2222 to the next kid, and so on. He then counts the number of windows in the room and chooses the volunteer with that number.
yes probabilites can be used to make fair ones
thanx
heya
![\dfrac{-40x^3-12x^2+16x}{-4x}=\dfrac{-40x^3}{-4x}+\dfrac{-12x^2}{-4x}+\dfrac{16x}{-4x}=10x^2+3x-4](https://tex.z-dn.net/?f=%20%5Cdfrac%7B-40x%5E3-12x%5E2%2B16x%7D%7B-4x%7D%3D%5Cdfrac%7B-40x%5E3%7D%7B-4x%7D%2B%5Cdfrac%7B-12x%5E2%7D%7B-4x%7D%2B%5Cdfrac%7B16x%7D%7B-4x%7D%3D10x%5E2%2B3x-4%20)
Answer: a- 10x^2 + 3x - 4
Answer:
There are 9 dimes and 15 nickels.
Step-by-step explanation:
Let number of dimes be 'd' and number of nickels be 'n'.
Given:
Total amount Debi has = $1.65
Number of nickels is 6 more than dimes.
We know that,
1 dime = $0.10
∴ 'd' dimes = $![0.10d](https://tex.z-dn.net/?f=0.10d)
1 nickel = $0.05
∴ 'n' nickels = $![0.05n](https://tex.z-dn.net/?f=0.05n)
As per question,
Number of nickels = 6 + number of dimes
∴
--------1
Also, total amount = $1.65
∴
------2
Now, solving equations (1) and (2) for 'n' and 'd'.
Plug in the value of 'n' from equation (1) in equation (2). This gives,
![0.10d+0.05(6+d)=1.65\\0.10d+0.30+0.05d=1.65\\0.10d+0.05d=1.65-0.30\\0.15d=1.35\\d=\frac{1.35}{0.15}=9](https://tex.z-dn.net/?f=0.10d%2B0.05%286%2Bd%29%3D1.65%5C%5C0.10d%2B0.30%2B0.05d%3D1.65%5C%5C0.10d%2B0.05d%3D1.65-0.30%5C%5C0.15d%3D1.35%5C%5Cd%3D%5Cfrac%7B1.35%7D%7B0.15%7D%3D9)
Therefore, the number of dimes are 9.
Number of nickels are = 9 + 6 = 15
Answer:
x-1÷2/5=x+1÷3/5
Step-by-step explanation:
Hint: Is means equals.