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3 years ago

Help Me !!! ASAP!!!!

Mathematics

1 answer:

bekas [8.4K]3 years ago

4 0

Answer:

#7 is 40

#8 is 50

#9 is 90

#10 is 180

#11 is 140

#12 is 130

#13 is 220

Sorry I have to go

Step-by-step explanation:

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Margot's dad has 7 striped ties and 21 solid ties. What is ratio striped ties to solid ties

Anuta_ua [19.1K]

7 : 21

which can be simplified to 1 : 3 as both sides are divisible by 7

8 0

3 years ago

Unit 2

olga2289 [7]

Answer:

A. $6.67

Step-by-step explanation:

a) 2y -3x + 8

a) y = - 3/2x + 8/2

a) y = - 3/2x + 4

b) 5y - 15x = -30

b) 5y = 15x - 30

b) y = 15/5x - 30/5

b) y = 3x - 6

3x - 6 = 3/2x + 4

3x -3/2x = 4+6

3/2x = 10

x = (10) / (3/2) = $6.67

5 0

3 years ago

Find the slope of the line running<br> through these two points (-4,5) and (8,-3)

Artemon [7]

Answer:

The slope is

$\frac{-3-5}{8-(-4)} =\frac{-8}{8+4} =\frac{-8}{12} =-\frac{2}{3}$

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the lcm of 300,400 and 500

ruslelena [56]

1. Decompose all numbers into prime factors
300 2 150 2 75 3 25 5 5 5 1 400 2 200 2 100 2 50 2 25 5 5 5 1 500 2 250 2 125 5 25 5 5 5 1
2. Write all numbers as the product of its prime factors
Prime factors of 300 = 22 . 3 . 52
Prime factors of 400 = 24 . 52
Prime factors of 500 = 22 . 53
3. Choose the common and uncommon prime factors with the greatest exponent
Common prime factors: 2 , 5
Common prime factors with the greatest exponent: 24, 53
Uncommon prime factors: 3
Uncommon prime factors with the greatest exponent: 31
4. Calculate the Least Common Multiple or LCM
Remember, to find the LCM of several numbers you must multiply the common and uncommon prime factors with the greatest exponent of those numbers.
LCM = 24. 53. 31 = 6000

3 0

3 years ago

Read 2 more answers

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

4 years ago