1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Simora [160]
3 years ago
14

2x - 6y = - 24 and x + -5y = -22​by substitution

Mathematics
2 answers:
ololo11 [35]3 years ago
4 0
X-3y+12=0 and x-5y+22=0
Aleks [24]3 years ago
3 0

Answer:

2x-6y=-24

2x=-24+6y

x=-24+6y÷2

x=-12+3y equation 1

x+(-5y)=-22

-12+3y-5y=-22

-13-2y=-22

-2y=-22+13

-2y=-9

y=-9÷2

y=4.5equation 2

putting value of equation 2 in equation 1

x=-12+3y

x=-12+3×4.5

x=-12+13.5

x=1.5 answer!!!

You might be interested in
Solve algebraically 10+f=10
Sunny_sXe [5.5K]
10 + f = 10
-10         -10


f = 10 - 10

f = 0.
4 0
3 years ago
31 cups are = to how many gallons ​
Pavel [41]

The answer is 1.9 gallons

6 0
3 years ago
Read 2 more answers
Consider the limit of rational function p(x)l q(x)
Helga [31]

#1

\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{0}{1}=0

  • The limit tends to 0
  • Hence c=0

\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{1}=1

  • Here limit tends to 1
  • Hence c=1

\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to 0}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{0}=\infty

  • Here x tends to infty.
  • c=infty

For the fourth one limit also tends to zero

8 0
3 years ago
Please help!!!!! This is due in a few hours...
Hunter-Best [27]
Peter's meal costed $8.11 in total. Hope this helps :D
7 0
3 years ago
Find the nth degree polynomial function with real coefficients satisfying the given conditions.
RUDIKE [14]
\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------

\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60
4 0
3 years ago
Other questions:
  • How do you solve this 42/3÷36
    13·2 answers
  • What is the sum of the solutions for 6x^2 − x − 2 = 0?
    8·1 answer
  • Whats the meaning of the tiatary industry​
    13·2 answers
  • #8 You make $114 for 12<br> hours of work. Find the unit<br> rate.
    15·2 answers
  • A sixth grade class receives 45% of the total proceeds of a candy sale. How many dollars does the class earn if the total sales
    14·1 answer
  • What is 2X + 2X +2 = 4X +2
    6·1 answer
  • Explain how you know that each pair of triangles are similar.
    12·1 answer
  • HELP PLEASE!!Which of the following is an asymptote for the graph below?
    10·1 answer
  • I need a fast help please
    7·1 answer
  • Can someone help ill give brainliest
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!