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2 years ago

6

the question is in the attachment. i know its not A because these angles are not opposite of each other.

1 answer:

Nutka1998 [239]2 years ago

8 0

Answer:

hi, it's b because a+b is 180°

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Ester sarai and kurry chose a number esters number is 1/10 of saris kurrys number is 10 times as much as sarais sarais number is

Tom [10]

Ester, Sarai, and Kurry each selected a number: 0.009, 0.09, and 0.9, respectively.

One of the four fundamental mathematical operations, along with addition, subtraction, and division, is multiplication. Multiply in mathematics refers to the continual addition of sets of identical sizes. For instance, 3+3+3+3+3 can be expressed as 3 5.

the ester's number is equal to one-tenth of the Sarai number.

= 1 / 10 × 0.09 = 0.009

to determine Kurry's number, multiply Sarai's number by 10

= 10 × 0.09 = 0.9

Therefore, it can be inferred that Kurry chose 0.9, Ester chose 0.009, and Sarai chose 0.09.

To know more about Multiplication, refer to this link:

brainly.com/question/10873737

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1 year ago

A petting zoo gives out large buckets of healthy popcorn snacks for visitors to feed to the animals. what fraction of the snack

LuckyWell [14K]

Cow- 1/3 = 12/36
goose- 1/12 = 3/36
goat= 2/9 = 8/36

12 + 3 + 8 = 23/36

23/36 is the fraction of the snack left

7 0

3 years ago

Read 2 more answers

Which of the following geometric objects could have it length measured

anastassius [24]

Answer:

You need to attach the image

Step-by-step explanation:

3 0

2 years ago

Someone please help me im so confused

ivann1987 [24]

Answer:

x=11

Step-by-step explanation:

5x+62=3x+47+37

5x+62=3x+84

2x=22

x=11

5 0

3 years ago

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

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3 0

1 year ago