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Irina-Kira [14]
3 years ago
13

Five children have heights of 138cm, 135cm, 140cm, 139cm, and 141cm.

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

6 cm

Step-by-step explanation:

To find the range take the largest number and subtract the smallest number

The largest number is 141 and the smallest number is 135

141 - 135 = 6 cm

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denis-greek [22]

Answer:

do 24 points i know it very well

8 0
3 years ago
**Solve by Elimination<br> 3 + 2x - y = 0<br> -3-7y = 10x<br> 7) x =<br> 8) y =
timofeeve [1]
Answer:

Explanation:

3 + 2x - y = 0
Or 2x - y = -3 (1)

-3-7y = 10x
Or -10x - 7y = 3 (2)

2x - y = -3 (1)
-10x - 7y = 3 (2)
———————

Multiply 5 to (1)

5(2x - y = -3)
-10x - 7y = 3
———————
10x - 5y = -15
-10x - 7y = 3
———————
-12y = -12
y = -12/-12
y = 1

Plug y value in (1)

2x - 1 = -3
2x = -3 + 1
2x = -2
x = -2/2 = -1

Therefore, x = -1 and y = 1
7 0
3 years ago
Find f¹(x) for the function<br> f(x) = -4.<br> 2<br> f¹(x) = [?]x + [ ]
g100num [7]

Answer:

{f}^{ - 1}(x)  = 2x + 8

Step-by-step explanation:

f(x) =  \frac{x}{2}  - 4 \\ \\  y = \frac{x}{2}   - 4 \\ \\ y =  \frac{x - 8}{2}   \\  \\ x = 2y + 8 \\  \\  {f}^{ - 1} (x) = 2x + 8

4 0
2 years ago
2. At the local park, there is an annual fair that
mafiozo [28]

Answer:

132 children and 88 adults

Step-by-step explanation:

let x represent the amount of kids and y represent the amount of adults.

since the problem says there was a total of 220 people at the fair an equation can be made

x+y=220

the problem tells that each childrens ticket was 1.5$ and each adult ticket was $4 and that a total of $550 was made that day, we can use the knowledge to make an equation:

1.5x + 4y = 550

using the equations we can make this systems of equations:

1.5x + 4y =550

x + y =220

solve the systems of equations by subracting y on both sides of th bottom equation:

x=220-y

since x is equivant to 220-y it can be substitued for x in the first equation to make this:

1.5(220-y)+4y =550

--solve for y--

y=88  - there were 88 adults

substute 88 for y in the second equation

x+88=220

--solve for x--

x=138 - there were 132 children

7 0
3 years ago
N = {X:X<br>is an odd number, 21&lt;x&lt;3<br>XEN]​
SIZIF [17.4K]
So it’s saying that the following set in roster form: (1) N = (x :x is an odd number, 21< × ≤ 35,×€ N)?

It seems to be that the Roster form would do not do anything but the thing is that this listing would give us the output of a set from this problem.

Your answer would be, N = Set of Odd Numbers such that x is greater than 21 and less than or equal to 35 = {23, 25, 27, 29, 31, 33, 35}.
5 0
3 years ago
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