Answer:
The linear function with the smallest slope must be multiple of one of the other two linear functions if all functions are coplanar. Otherwise, they intersect at the given point in space.
Step-by-step explanation:
A system of two linear functions with two variables have an unique solution on a given plane, as there are three linear function, it means that linear function with the smallest slope must be multiple of one of the other two linear functions.
But, if those functions are not all coplanar and have 3 variables, they intersect at the given point.
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Number of cubes increases by 3 for each term.
an= 3n+1
Answer:
The amount that would be in the account after 30 years is $368,353
Step-by-step explanation:
Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly
We proceed to use the formula below;
A = [P(1 + r)^t-1]/r
From the question;
P is the amount deposited yearly which is $4,500
r is the interest rate = 2.5% = 2.5/100 = 0.025
t is the number of years which is 30
Substituting these values into the equation, we have;
A = [4500(1 + 0.025)^30-1]/0.025
A = [4500(1.025)^29]/0.025
A = 368,353.3309607034
To the nearest whole dollars, this is;
$368,353
