What is the answer?

Please help.... this is confusing me:0

JulsSmile [24]

Answer:

See below

Step-by-step explanation:

IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!

sin z = O/H = opposite side/hypotenuse = 16/20

cos z = A/H = adjacent / hy[potenuse = 12/20

tan z = O/A = 16/12

5 0

2 years ago

What is the slope of a line that is perpendicular to the line whose equation is 0.52 - 5y = 9?

otez555 [7]

The slope is 0.1
To find a perpendicular slope, find the negative reciprocal.
The reciprocal of 0.1 is 10
The negative of 10 is -10
Final answer:-10

7 0

3 years ago

Kevin and Randy Muise have a jar containing 47 coins, all of which are either quarters or nickels. The total value of the coins

SVETLANKA909090 [29]

Ik but learn its simple but there is multiple answers

4 0

3 years ago

Select the polynomial that is a perfect square trinomial. 36x2 − 4x 16 16x2 − 8x 36 25x2 9x 4 4x2 20x 25.

Naya [18.7K]

The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.

The given polynomial is

$a) 36x^2-4x+16$

What is the form of perfect square polynomial?

$(ax+b)^2$

we solve this method by using perfect square method

add and subtract 1/9

$36x^2-4x+16+\frac{1}{9}-\frac{1}{9}$

factor 36

$\frac{143}{9}+36(x^2-\frac{x}{9}+\frac{1}{324} )$

Now complete the square

$\frac{143}{9}+36(x^2-\frac{1}{18})^2$

Therefore this is not perfect square trinomial.

Similarly for

$b) 16x^2-8x+36$

Complete square is,

$16(x-\frac{1}{4})^2+35$

This polynomial is also not perfect square trinomial.

$c) 25x^2+9x+4\\$

complete square is,

$25(x+\frac{9}{50})^2+\frac{319}{100}$

This polynomial is not perfect square trinomial.

$d)4x^2+20x+25\\$

complete square is,

$(2x+5)^2$

This polynomial is perfect square trinomial.

Therefore,

The polynomial a,b,c,are not perfect square polynomial and the polynomial d is perfect square polynomial.

To learn more about perfect square trinomial visit:

brainly.com/question/1538726

3 0

2 years ago

Please help will give brainliest brainliest

Ad libitum [116K]

Answer:

D. $A\subset \mathbb{R}\times\mathbb{R}.$

Step-by-step explanation:

Consider the set

$A=\left\{(2,3),\ (5,1),\ (-3,-2),\ (0,3)\right\}$

This set consists of four ordered pairs.

The first numbers in these pairs are $2,\ 5,\ -3,\ 0.$ These numbers are integer numbers (not natural, because -3 is negative).

The second numbers in these pairs are $3,\ 1,\ -2,\ 3.$ These numbers are integer numbers too (not natural, because -2 is negative).

Options contain only natural and real sets, so, the first and the second numbers are real numbers and

$A\subset \mathbb{R}\times\mathbb{R}.$

8 0

3 years ago

Read 2 more answers