Since we know a triangle only has 180 degrees we can say:
99+3x+x+5=180
Then we can solve for x:
4x+104=180
4x=76
x=19
<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
the second one, and the third one
Answer:
Step 1: Simplify both sides of the equation.
6(3x−5)−7x=25
(6)(3x)+(6)(−5)+−7x=25(Distribute)
18x+−30+−7x=25
(18x+−7x)+(−30)=25(Combine Like Terms)
11x+−30=25
11x−30=25
Step 2: Add 30 to both sides.
11x−30+30=25+30
11x=55
Step 3: Divide both sides by 11.
x=5
Step-by-step explanation: